A satellite moving is orbiting in the equatorial plane with a period from period from perigee to perigee of 12hrs.Given the eccentricity is 0.02. Calculate the semimajor axis. The earth’s equatorial radius is 6378.1414 km.

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Given e=0.02 µ=3.986005×1014 αE=6378.1414km

Mean motion n=2π/p=2π/12=1.454×10-4s-1

a=(µ/n2)1/3=26610km.

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